What is the derivative of f(t)=5t-9t^2 ?

The derivative of f(t)=5t-9t^2 is 5-18t

What is the first derivative of f(t)=5t-9t^2 ?

The first derivative of f(t)=5t-9t^2 is 5-18t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (t) = 5 t - 9 t^{2}

5 - 18 t

Solution steps

\frac{d}{d t} (5 t - 9 t^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (5 t) - \frac{d}{d t} (9 t^{2})

\frac{d}{d t} (5 t) = 5

\frac{d}{d t} (9 t^{2}) = 18 t

= 5 - 18 t

\frac{\partial}{\partial x} (x^{2} - x y + y^{2} + 3 x - 2 y + 1)

y^{2} = 2 x y y^{^{'}}

x \to - 1 lim (2)

\frac{\partial}{\partial x} (\frac{x}{x ^{2}})

y^{^{'}} + \frac{3}{x} y = \frac{1}{x ^{2}}

What is the derivative of f(t)=5t-9t^2 ?
The derivative of f(t)=5t-9t^2 is 5-18t
What is the first derivative of f(t)=5t-9t^2 ?
The first derivative of f(t)=5t-9t^2 is 5-18t