What is (\partial)/(\partial y)((-y)/(x^2+9y^2)) ?

The answer to (\partial)/(\partial y)((-y)/(x^2+9y^2)) is -(x^2-9y^2)/((x^2+9y^2)^2)

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(\partial)/(\partial y)((-y)/(x^2+9y^2))

\frac{\partial}{\partial y} (\frac{- y}{x ^{2} + 9 y ^{2}})

- \frac{x ^{2} - 9 y ^{2}}{( x ^{2} + 9 y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{- y}{x ^{2} + 9 y ^{2}})

Simplify

\frac{- y}{x ^{2} + 9 y ^{2}} : - \frac{y}{x ^{2} + 9 y ^{2}}

= \frac{\partial}{\partial y} (- \frac{y}{x ^{2} + 9 y ^{2}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial y} (\frac{y}{x ^{2} + 9 y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - \frac{\frac{\partial}{\partial y} ( y ) ( x ^{2} + 9 y ^{2} ) - \frac{\partial}{\partial y} ( x ^{2} + 9 y ^{2} ) y}{( x ^{2} + 9 y ^{2} ) ^{2}}

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x^{2} + 9 y^{2}) = 18 y

= - \frac{1 \cdot ( x ^{2} + 9 y ^{2} ) - 18 yy}{( x ^{2} + 9 y ^{2} ) ^{2}}

1 \cdot (x^{2} + 9 y^{2}) - 18 yy = x^{2} - 9 y^{2}

= - \frac{x ^{2} - 9 y ^{2}}{( x ^{2} + 9 y ^{2} ) ^{2}}

\int_{- 2}^{3} \frac{40}{x ^{4}} d x

y = x + 3

\frac{1}{s} - \frac{2}{( s + 3 ) ^{2} - 9}

\int \frac{2 x ^{2} - 1}{x ^{3} - x} d x

\int \frac{1}{x ^{4} + y ^{2}} d y

What is (\partial)/(\partial y)((-y)/(x^2+9y^2)) ?
The answer to (\partial)/(\partial y)((-y)/(x^2+9y^2)) is -(x^2-9y^2)/((x^2+9y^2)^2)