What is the derivative of 2e^xcos(sqrt(2)x) ?

The derivative of 2e^xcos(sqrt(2)x) is 2(e^xcos(sqrt(2)x)-sqrt(2)e^xsin(sqrt(2)x))

What is the first derivative of 2e^xcos(sqrt(2)x) ?

The first derivative of 2e^xcos(sqrt(2)x) is 2(e^xcos(sqrt(2)x)-sqrt(2)e^xsin(sqrt(2)x))

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\frac{d}{d x} (2 e^{x} cos (2 x))

2 (e^{x} cos (2 x) - 2 e^{x} sin (2 x))

Solution steps

\frac{d}{d x} (2 e^{x} cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{x} cos (2 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (2 x)

= 2 (\frac{d}{d x} (e^{x}) cos (2 x) + \frac{d}{d x} (cos (2 x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (2 x)) = - sin (2 x) 2

= 2 (e^{x} cos (2 x) + (- sin (2 x) 2) e^{x})

Simplify

= 2 (e^{x} cos (2 x) - 2 e^{x} sin (2 x))

y = 1.45 e^{59.9 t} sin (201 t)

\int_{2}^{6} t^{4} ln (3 t) d t

f (x) = x^{2} - 16

y = \frac{3}{x} + 2 x^{3}, 2 \leq x \leq 3

f (x) = - 2 x^{3}, (1, - 2)

What is the derivative of 2e^xcos(sqrt(2)x) ?
The derivative of 2e^xcos(sqrt(2)x) is 2(e^xcos(sqrt(2)x)-sqrt(2)e^xsin(sqrt(2)x))
What is the first derivative of 2e^xcos(sqrt(2)x) ?
The first derivative of 2e^xcos(sqrt(2)x) is 2(e^xcos(sqrt(2)x)-sqrt(2)e^xsin(sqrt(2)x))