What is the sum from n=2 to infinity of n/(2n^2-3) ?

The sum from n=2 to infinity of n/(2n^2-3) is diverges

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sum from n=2 to infinity of n/(2n^2-3)

n = 2 \sum \infty \frac{n}{2 n ^{2} - 3}

diverges

Solution steps

n = 2 \sum \infty \frac{n}{2 n ^{2} - 3}

Apply Series Comparison Test:

diverges

= diverges

\frac{\partial}{\partial x} (e^{- x y} + y^{3} x^{4})

\frac{d}{d x} (3 x^{3} + 2 x^{2} - 1 x + 5)

\int_{0}^{3} e^{- x^{2}} d x

x \to π lim (ln (cos (x) - 3))

\int y^{2} z + 2 x z^{2} d x

What is the sum from n=2 to infinity of n/(2n^2-3) ?
The sum from n=2 to infinity of n/(2n^2-3) is diverges