What is the derivative of xe^x+2e^x ?

The derivative of xe^x+2e^x is e^xx+3e^x

What is the first derivative of xe^x+2e^x ?

The first derivative of xe^x+2e^x is e^xx+3e^x

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\frac{d}{d x} (x e^{x} + 2 e^{x})

e^{x} x + 3 e^{x}

Solution steps

\frac{d}{d x} (x e^{x} + 2 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x e^{x}) + \frac{d}{d x} (2 e^{x})

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

= e^{x} + e^{x} x + 2 e^{x}

Simplify

= e^{x} x + 3 e^{x}

2 y^{^{'}} = y^{3} cos (x)

x \to 0 lim (x^{4} sin (\frac{2}{x}))

g (u) = 7 u + 13 u

\frac{\partial}{\partial x} (x e^{3 x y})

\int \frac{cos ( 2 x )}{x} d x

What is the derivative of xe^x+2e^x ?
The derivative of xe^x+2e^x is e^xx+3e^x
What is the first derivative of xe^x+2e^x ?
The first derivative of xe^x+2e^x is e^xx+3e^x