What is the integral of 9cos(t) ?

The integral of 9cos(t) is 9sin(t)+C

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integral of 9cos(t)

\int 9 cos (t) d t

9 sin (t) + C

Solution steps

\int 9 cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= 9 sin (t)

Add a constant to the solution

= 9 sin (t) + C

\frac{ln ( x )}{x}

\int \frac{x ^{2} - 3 x - 10}{x + 2} d x

x \to 0 + lim (x cos (\frac{3}{x}))

x \to 1 + lim (2 x - 1)

\frac{d}{d x} (3 x ln (x))