What is the integral of x^2sqrt(x^3+17) ?

The integral of x^2sqrt(x^3+17) is 2/9 (x^3+17)^{3/2}+C

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integral of x^2sqrt(x^3+17)

\int x^{2} x^{3} + 17 d x

\frac{2}{9} (x^{3} + 17)^{\frac{3}{2}} + C

Solution steps

\int x^{2} x^{3} + 17 d x

Apply u-substitution

: \int \frac{u}{3} d u

= \int \frac{u}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{3} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x^{3} + 17

= \frac{1}{3} \cdot \frac{2}{3} (x^{3} + 17)^{\frac{3}{2}}

Simplify

\frac{1}{3} \cdot \frac{2}{3} (x^{3} + 17)^{\frac{3}{2}} : \frac{2}{9} (x^{3} + 17)^{\frac{3}{2}}

= \frac{2}{9} (x^{3} + 17)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{9} (x^{3} + 17)^{\frac{3}{2}} + C

\frac{d}{d x} (x^{\frac{1}{2}} ln (x))

\frac{d}{d x} ((2 x^{2} - 5)^{- 12})

\frac{\partial}{\partial u} (\frac{( u + v )}{2})

\frac{\partial}{\partial x} (x^{2} y cos (\frac{z}{t}))

\frac{\partial}{\partial x} (\frac{- 3 x - y}{y ^{2} + 2 x ^{2}})

What is the integral of x^2sqrt(x^3+17) ?
The integral of x^2sqrt(x^3+17) is 2/9 (x^3+17)^{3/2}+C