What is the solution for (dy}{dx}=\frac{(y^2-y))/x ?

The solution for (dy}{dx}=\frac{(y^2-y))/x is y= 1/(1-c_{1)x}

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(dy}{dx}=\frac{(y^2-y))/x

\frac{d y}{d x} = \frac{( y ^{2} - y )}{x}

y = \frac{1}{1 - c _{1} x}

Solution steps

\frac{d y}{d x} = \frac{( y ^{2} - y )}{x}

Solve separable ODE:

y = \frac{1}{1 - c _{1} x}

y = \frac{1}{1 - c _{1} x}

\frac{\partial}{\partial x} (x e^{x} + 2 e^{x} y)

e^{x} x^{7} + 14 e^{x} x^{6} + 42 e^{x} x^{5}

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\int_{2}^{\infty} x e^{- 6 x} d x

y^{^{'}} (3 x + \frac{1}{y}) + 3 y + e^{x} = 0

What is the solution for (dy}{dx}=\frac{(y^2-y))/x ?
The solution for (dy}{dx}=\frac{(y^2-y))/x is y= 1/(1-c_{1)x}