What is the tangent of f(x)=-2cos(x),\at x=-pi ?

The tangent of f(x)=-2cos(x),\at x=-pi is y=2

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tangent of f(x)=-2cos(x),\at x=-pi

tangent of

f (x) = - 2 cos (x), at x = - π

y = 2

Solution steps

Find the tangent point:

(- π, 2)

Find the slope of

f (x) = - 2 cos (x) : \frac{df ( x )}{d x} = 2 sin (x)

Compute the slope of

f (x) = - 2 cos (x)

x = - π : m = 0

Find the line with slope m=

0

and passing through

(- π, 2) : y = 2

y = 2

\frac{\partial}{\partial y} (2 x yz)

\int \frac{sec ( x ) tan ( x )}{tan ( x )} d x

x + 1

f (x) = 2 x - 1

x \to \infty lim (\frac{- 1 ^{x + 1} x}{x + x})

What is the tangent of f(x)=-2cos(x),\at x=-pi ?
The tangent of f(x)=-2cos(x),\at x=-pi is y=2