What is (\partial)/(\partial y)(2xyz) ?

The answer to (\partial)/(\partial y)(2xyz) is 2xz

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(\partial)/(\partial y)(2xyz)

\frac{\partial}{\partial y} (2 x yz)

2 x z

Solution steps

\frac{\partial}{\partial y} (2 x yz)

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x z \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= 2 x z \cdot 1

Simplify

= 2 x z

\int \frac{sec ( x ) tan ( x )}{tan ( x )} d x

x + 1

f (x) = 2 x - 1

x \to \infty lim (\frac{- 1 ^{x + 1} x}{x + x})

\int \frac{sin ( 2 x )}{39 + cos ^{2} ( x )} d x

What is (\partial)/(\partial y)(2xyz) ?
The answer to (\partial)/(\partial y)(2xyz) is 2xz