What is the solution for y^'=((4x^3+y^3))/(xy^2) ?

The solution for y^'=((4x^3+y^3))/(xy^2) is y=x\sqrt[3]{12ln(x)+c_{1}}

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y^'=((4x^3+y^3))/(xy^2)

y^{^{'}} = \frac{( 4 x ^{3} + y ^{3} )}{x y ^{2}}

Solution steps

y^{'} (x) = \frac{( 4 x ^{3} + y ^{3} )}{x y ^{2}}

Solve Bernoulli ODE:

n = 0 \sum \infty \frac{1}{2 n !}

y^{^{'}} = cos^{2} (y) ln (x)

\frac{\partial}{\partial x} (e^{5 x} sin (5 y))

\frac{x ^{2} - 1}{x ^{2} + x + 1}

y = - \frac{2}{x ^{2}}

What is the solution for y^'=((4x^3+y^3))/(xy^2) ?
The solution for y^'=((4x^3+y^3))/(xy^2) is y=x\sqrt[3]{12ln(x)+c_{1}}