What is the first derivative of 3^3 ?

The first derivative of 3^3 is 0

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derivative of 3^3

\frac{d}{d x} (3^{3})

0

Solution steps

\frac{d}{d x} (3^{3})

3^{3} = 27

= \frac{d}{d x} (27)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int \frac{x ^{2} - 5 x - 6}{x ^{2} - 4} d x

\frac{\partial}{\partial x} (3 x e^{2 x y})

\int_{0}^{l n (4)} π (e^{- x})^{2} d x

\frac{\partial}{\partial x} ((1 + x^{2})^{z s i n (y)})

t an g e n t f (x) = \frac{( x + 1 )}{( x - 1 )}