What is the limit as x approaches 0 of (sin(pi+x))/x ?

The limit as x approaches 0 of (sin(pi+x))/x is -1

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limit as x approaches 0 of (sin(pi+x))/x

x \to 0 lim (\frac{sin ( π + x )}{x})

- 1

Solution steps

x \to 0 lim (\frac{sin ( π + x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{- cos ( x )}{1})

= x \to 0 lim (\frac{- cos ( x )}{1})

Plug in the value

x = 0

= \frac{- cos ( 0 )}{1}

Simplify

\frac{- cos ( 0 )}{1} : - 1

= - 1

y = 12, y = 2 x^{2} - 11 x + 12

f (x) = 2 x^{7} - 3 x^{6} + 3 x^{3} - 4 x^{2} - 7

\frac{d}{d x} (ln (x^{2}) (3 x^{2} + 6))

\int_{2}^{5} (- 3 v + 4) d v

\frac{d y}{d x} = \frac{( x ^{2} - y ^{2} )}{3 x y}

What is the limit as x approaches 0 of (sin(pi+x))/x ?
The limit as x approaches 0 of (sin(pi+x))/x is -1