What is the limit as x approaches+0+of 2/(1+ln(x)) ?

The limit as x approaches+0+of 2/(1+ln(x)) is 0

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limit as x approaches+0+of 2/(1+ln(x))

x \to + 0 + lim (\frac{2}{1 + ln ( x )})

0

Solution steps

x \to 0 + lim (\frac{2}{1 + ln ( x )})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 2 \cdot x \to 0 + lim (\frac{1}{1 + ln ( x )})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= 2 \cdot \frac{lim _{x \to 0 +} ( 1 )}{lim _{x \to 0 +} ( 1 + ln ( x ) )}

x \to 0 + lim (1) = 1

x \to 0 + lim (1 + ln (x)) = - \infty

= 2 \cdot \frac{1}{- \infty}

Simplify

2 \cdot \frac{1}{- \infty} : 0

= 0

y = 4 x - x^{2}

\int 20 t (5 t^{2} - 3)^{3} d t

n = 5 \sum \infty \frac{1}{n ln ( n )}

\frac{d}{d x} (\frac{( 2 x ^{3} + 7 ) ( 3 x ^{2} - 5 )}{x ^{2} + 1})

x \to 7 lim (\frac{3}{( x - 7 ) ^{2}})

What is the limit as x approaches+0+of 2/(1+ln(x)) ?
The limit as x approaches+0+of 2/(1+ln(x)) is 0