What is laplacetransform 5+4\delta(t) ?

The answer to laplacetransform 5+4\delta(t) is 5/s+4

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laplacetransform 5+4\delta(t)

laplace transform

5 + 4 δ (t)

\frac{5}{s} + 4

Solution steps

L {5 + 4 δ (t)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {5} + 4 L {δ (t)}

L {5} : \frac{5}{s}

L {δ (t)} : 1

= \frac{5}{s} + 4 \cdot 1

Refine

\frac{5}{s} + 41 : \frac{5}{s} + 4

= \frac{5}{s} + 4

\int 4^{s i n (x)} cos (x) d x

x \to - 7 lim (\frac{x + 8}{x + 7})

\frac{d}{d x} (e^{x - 3})

2 x^{5}

\int e^{- 5 x} sin (x) d x

What is laplacetransform 5+4\delta(t) ?
The answer to laplacetransform 5+4\delta(t) is 5/s+4