What is the derivative of f(x)=16\sqrt[4]{x} ?

The derivative of f(x)=16\sqrt[4]{x} is 4/(x^{3/4)}

What is the first derivative of f(x)=16\sqrt[4]{x} ?

The first derivative of f(x)=16\sqrt[4]{x} is 4/(x^{3/4)}

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derivative of

\frac{4}{x ^{\frac{3}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 16 \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 \cdot \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

16 \cdot \frac{1}{4} x^{\frac{1}{4} - 1} : \frac{4}{x ^{\frac{3}{4}}}

= \frac{4}{x ^{\frac{3}{4}}}

\int \frac{sin ^{7} ( 10 x )}{cos ^{4} ( 10 x )} d x

\frac{\partial}{\partial y} (f (x, y) (x + y))

f (x) = x + 13

x y^{^{'}} - y = - 2 x^{2} - 2 x + 1

\frac{\partial}{\partial z} (x y^{2} e^{y})

What is the derivative of f(x)=16\sqrt[4]{x} ?
The derivative of f(x)=16\sqrt[4]{x} is 4/(x^{3/4)}
What is the first derivative of f(x)=16\sqrt[4]{x} ?
The first derivative of f(x)=16\sqrt[4]{x} is 4/(x^{3/4)}