What is the derivative of (7e^x/(2e^x+1)) ?

The derivative of (7e^x/(2e^x+1)) is (7e^x)/((2e^x+1)^2)

What is the first derivative of (7e^x/(2e^x+1)) ?

The first derivative of (7e^x/(2e^x+1)) is (7e^x)/((2e^x+1)^2)

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Popular >

\frac{d}{d x} (\frac{7 e ^{x}}{2 e ^{x} + 1})

\frac{7 e ^{x}}{( 2 e ^{x} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7 e ^{x}}{2 e ^{x} + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{e ^{x}}{2 e ^{x} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 7 \cdot \frac{\frac{d}{d x} ( e ^{x} ) ( 2 e ^{x} + 1 ) - \frac{d}{d x} ( 2 e ^{x} + 1 ) e ^{x}}{( 2 e ^{x} + 1 ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2 e^{x} + 1) = 2 e^{x}

= 7 \cdot \frac{e ^{x} ( 2 e ^{x} + 1 ) - 2 e ^{x} e ^{x}}{( 2 e ^{x} + 1 ) ^{2}}

Simplify

7 \cdot \frac{e ^{x} ( 2 e ^{x} + 1 ) - 2 e ^{x} e ^{x}}{( 2 e ^{x} + 1 ) ^{2}} : \frac{7 e ^{x}}{( 2 e ^{x} + 1 ) ^{2}}

= \frac{7 e ^{x}}{( 2 e ^{x} + 1 ) ^{2}}

\int \frac{e ^{x}}{e ^{2 x} - 2 e ^{x} - 3} d x

\frac{x ^{3} - x}{1 + x ^{2}}

f (x) = x^{2} - x, (- 4, 20)

x \cdot y \cdot \frac{d y}{d x} - y^{2} = 2 \cdot x^{2}

n = 4 \sum \infty \frac{1}{n ( n + 1 )}

What is the derivative of (7e^x/(2e^x+1)) ?
The derivative of (7e^x/(2e^x+1)) is (7e^x)/((2e^x+1)^2)
What is the first derivative of (7e^x/(2e^x+1)) ?
The first derivative of (7e^x/(2e^x+1)) is (7e^x)/((2e^x+1)^2)