What is the solution for (dy)/(dx)+2/x y=(sin(x))/(x^2) ?

The solution for (dy)/(dx)+2/x y=(sin(x))/(x^2) is y=-(cos(x))/(x^2)+(c_{1})/(x^2)

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(dy)/(dx)+2/x y=(sin(x))/(x^2)

\frac{d y}{d x} + \frac{2}{x} y = \frac{sin ( x )}{x ^{2}}

y = - \frac{cos ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

\frac{d y}{d x} + \frac{2}{x} y = \frac{sin ( x )}{x ^{2}}

Solve linear ODE:

y = - \frac{cos ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

y = - \frac{cos ( x )}{x ^{2}} + \frac{c _{1}}{x ^{2}}

\int_{0}^{2} \frac{1}{x + 3} d x

cos (2 y)

\int \frac{1}{y ^{2} - 1} d y

n = 2 \sum \infty \frac{1}{n ( n + 2 )}

x y^{^{'}} + 2 y = 9 x

What is the solution for (dy)/(dx)+2/x y=(sin(x))/(x^2) ?
The solution for (dy)/(dx)+2/x y=(sin(x))/(x^2) is y=-(cos(x))/(x^2)+(c_{1})/(x^2)