What is the sum from n=1 to infinity}((4)^{n-1 of)/(5^n) ?

The sum from n=1 to infinity}((4)^{n-1 of)/(5^n) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity}((4)^{n-1 of)/(5^n)

n = 1 \sum \infty \frac{( 4 ) ^{n - 1}}{5 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{4 ^{n - 1}}{5 ^{n}}

Apply Series Ratio Test:

converges

= converges

4 ln (7 + 2 x^{2})

f (x) = \frac{1}{x ^{6}}

sec (x) - 6 cos (x)

\frac{\partial}{\partial y} (x^{y} - x y)

\frac{d y}{d x} = 2 x e^{y}

What is the sum from n=1 to infinity}((4)^{n-1 of)/(5^n) ?
The sum from n=1 to infinity}((4)^{n-1 of)/(5^n) is converges