What is the solution for y^'+sin(t)y=sin(t),y(0)=6 ?

The solution for y^'+sin(t)y=sin(t),y(0)=6 is y=5e^{cos(t)-1}+1

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y^'+sin(t)y=sin(t),y(0)=6

y^{^{'}} + sin (t) y = sin (t), y (0) = 6

y = 5 e^{c o s (t) - 1} + 1

Solution steps

y^{'} (t) + sin (t) y = sin (t)

Solve separable ODE:

y = 5 e^{c o s (t) - 1} + 1

y = 5 e^{c o s (t) - 1} + 1

\frac{\partial}{\partial x} ((x^{2} - 2 x) cos (y))

\frac{d}{d x} ((e^{3 x}) (cos (2 x)))

16 y^{''} + 8 y^{'} + y = 0

x \to 0 lim (\frac{tan ( 4 x ) cos ( 6 x ) - tan ( 4 x )}{24 x ^{3}})

x \to + 1 lim (\frac{x - 1}{x ^{6} - 1})

What is the solution for y^'+sin(t)y=sin(t),y(0)=6 ?
The solution for y^'+sin(t)y=sin(t),y(0)=6 is y=5e^{cos(t)-1}+1