What is (\partial)/(\partial x)(e^{2y-x}) ?

The answer to (\partial)/(\partial x)(e^{2y-x}) is -e^{2y-x}

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(\partial)/(\partial x)(e^{2y-x})

\frac{\partial}{\partial x} (e^{2 y - x})

- e^{2 y - x}

Solution steps

\frac{\partial}{\partial x} (e^{2 y - x})

Treat

y

as a constant

Apply the chain rule:

e^{2 y - x} \frac{\partial}{\partial x} (2 y - x)

= e^{2 y - x} \frac{\partial}{\partial x} (2 y - x)

\frac{\partial}{\partial x} (2 y - x) = - 1

= e^{2 y - x} (- 1)

Simplify

= - e^{2 y - x}

\frac{x ^{2}}{x - 1}

\int 5 x^{2} sin (2 x) d x

\int cos^{3} (5 x) d x

\frac{d}{d x} ((x + 2)^{\frac{2}{3}})

y^{^{''}} + 4 y^{^{'}} = 0, y (0) = 1

What is (\partial)/(\partial x)(e^{2y-x}) ?
The answer to (\partial)/(\partial x)(e^{2y-x}) is -e^{2y-x}