What is the solution for 2xy(dy)/(dx)=y^2-x^2 ?

The solution for 2xy(dy)/(dx)=y^2-x^2 is y=sqrt(-x^2+c_{1)x},y=-sqrt(-x^2+c_{1)x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2xy(dy)/(dx)=y^2-x^2

2 x y \frac{d y}{d x} = y^{2} - x^{2}

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

Solution steps

2 x y \frac{d y}{d x} = y^{2} - x^{2}

Solve Bernoulli ODE:

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

\frac{d y}{d x} = 8 x y + 3 y

x \to 1 lim (6)

\int (1 - cos (x)) d x

\int \frac{1}{x ^{3} - 27} d x

\int \frac{x ^{3} + 7 x ^{2} + 25 x + 35}{x ^{2} + 5 x + 6} d x

What is the solution for 2xy(dy)/(dx)=y^2-x^2 ?
The solution for 2xy(dy)/(dx)=y^2-x^2 is y=sqrt(-x^2+c_{1)x},y=-sqrt(-x^2+c_{1)x}