What is the tangent of f(x)=2x^4-11x^2,\at x=1 ?

The tangent of f(x)=2x^4-11x^2,\at x=1 is y=-14x+5

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tangent of f(x)=2x^4-11x^2,\at x=1

tangent of

f (x) = 2 x^{4} - 11 x^{2}, at x = 1

y = - 14 x + 5

Solution steps

Find the tangent point:

(1, - 9)

Find the slope of

f (x) = 2 x^{4} - 11 x^{2} : \frac{df ( x )}{d x} = 8 x^{3} - 22 x

Compute the slope of

f (x) = 2 x^{4} - 11 x^{2}

x = 1 : m = - 14

Find the line with slope m=

- 14

and passing through

(1, - 9) : y = - 14 x + 5

y = - 14 x + 5

\int \frac{x}{2 x ^{2} + 3} d x

7 + e^{- 5 x} y^{^{'}} = 0

\int \frac{2 x - 1}{( x - 1 ) ( x - 2 )} d x

sin (w)

y^{^{''}} + 4 y^{^{'}} + 5 y = 15 x + e^{(- x)}

What is the tangent of f(x)=2x^4-11x^2,\at x=1 ?
The tangent of f(x)=2x^4-11x^2,\at x=1 is y=-14x+5