integral of-6cos(x)-4sin(x)-4

解答

\int - 6 cos (x) - 4 sin (x) - 4 d x

- 6 sin (x) + 4 cos (x) - 4 x + C

求解步骤

\int - 6 cos (x) - 4 sin (x) - 4 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 6 cos (x) d x - \int 4 sin (x) d x - \int 4 d x

\int 6 cos (x) d x = 6 sin (x)

\int 4 sin (x) d x = - 4 cos (x)

\int 4 d x = 4 x

= - 6 sin (x) - (- 4 cos (x)) - 4 x

化简

= - 6 sin (x) + 4 cos (x) - 4 x

解答补常数

= - 6 sin (x) + 4 cos (x) - 4 x + C

\int 4 x x d x

\int \frac{3 x - 1}{( x ^{2} + 1 ) ( x ^{2} + 2 x + 2 )} d x

\int \frac{( x + 1 ) ^{8}}{2 x} d x

\int 4 - 2 t d t

\int \frac{3 x ^{2}}{3} d x