What is the integral from 0 to 3 of 1/(x^4) ?

The integral from 0 to 3 of 1/(x^4) is diverges

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integral from 0 to 3 of 1/(x^4)

\int_{0}^{3} \frac{1}{x ^{4}} d x

diverges

Solution steps

\int_{0}^{3} \frac{1}{x ^{4}} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{0}^{3}

= [- \frac{1}{3 x ^{3}}]_{0}^{3}

Compute the boundaries:

diverges

= diverges

\int 18 cot^{4} (x) d x

\int y^{2} - 1 d y

f (x) = x^{3} - 2 x + 2, (4, 58)

e^{- t} (cos (4 t) - 2 sin (4 t))

\frac{d}{d t} (t^{2} e^{t})

What is the integral from 0 to 3 of 1/(x^4) ?
The integral from 0 to 3 of 1/(x^4) is diverges