What is the integral of (ln(2))/(x^2) ?

The integral of (ln(2))/(x^2) is -(ln(2))/x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (ln(2))/(x^2)

\int \frac{ln ( 2 )}{x ^{2}} d x

- \frac{ln ( 2 )}{x} + C

Solution steps

\int \frac{ln ( 2 )}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= ln (2) \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= ln (2) (- \frac{1}{x})

Simplify

ln (2) (- \frac{1}{x}) : - \frac{ln ( 2 )}{x}

= - \frac{ln ( 2 )}{x}

Add a constant to the solution

= - \frac{ln ( 2 )}{x} + C

y^{^{'}} = \frac{( 3 t ^{2} - e ^{t} )}{( 2 y - 5 )}, y (0) = 1

n = 1 \sum \infty ln (n + 2)

x \to 2 - lim (ln (x^{2} (3 - x)))

x^{2}, 2 - x^{2}

x \to 0 lim (\frac{1}{2})

What is the integral of (ln(2))/(x^2) ?
The integral of (ln(2))/(x^2) is -(ln(2))/x+C