What is the tangent of y=(4x)/(x+3),(1,1) ?

The tangent of y=(4x)/(x+3),(1,1) is y= 3/4 x+1/4

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tangent of y=(4x)/(x+3),(1,1)

tangent of

y = \frac{4 x}{x + 3}, (1, 1)

y = \frac{3}{4} x + \frac{1}{4}

Solution steps

Find the slope of

y = \frac{4 x}{x + 3} : \frac{d y}{d x} = \frac{12}{( x + 3 ) ^{2}}

Compute the slope of

y = \frac{4 x}{x + 3}

(1, 1) : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(1, 1) : y = \frac{3}{4} x + \frac{1}{4}

y = \frac{3}{4} x + \frac{1}{4}

\int x^{2} e^{x^{3 + 4}} d x

f (x) = lo g_{2} (2 x^{2} + 14), at x = 5

x \to 2 lim (\frac{0}{4})

\frac{1}{x - 1}, 5

y = 8 x - x^{2}

What is the tangent of y=(4x)/(x+3),(1,1) ?
The tangent of y=(4x)/(x+3),(1,1) is y= 3/4 x+1/4