What is the integral from 0 to 3 of 2e^x ?

The integral from 0 to 3 of 2e^x is 2(e^3-1)

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integral from 0 to 3 of 2e^x

\int_{0}^{3} 2 e^{x} d x

2 (e^{3} - 1)

Decimal Notation

38.17107 \dots

Solution steps

\int_{0}^{3} 2 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{3} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 2 [e^{x}]_{0}^{3}

Compute the boundaries:

e^{3} - 1

= 2 (e^{3} - 1)

\frac{d}{d x} (ln (x) - \frac{x ^{2}}{8})

x \to - 3 lim ((x - 5) (x + 4))

\int_{0}^{\infty} \frac{1}{4 + x} d x

x \to 0 lim (\frac{x}{1 - ( x - 1 ) ^{2}})

t \to 0 + lim (arctan (ln (t)))

What is the integral from 0 to 3 of 2e^x ?
The integral from 0 to 3 of 2e^x is 2(e^3-1)