What is the limit as t approaches-infinity of e^t+1 ?

The limit as t approaches-infinity of e^t+1 is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as t approaches-infinity of e^t+1

t \to - \infty lim (e^{t} + 1)

1

Solution steps

t \to - \infty lim (e^{t} + 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= t \to - \infty lim (e^{t}) + t \to - \infty lim (1)

t \to - \infty lim (e^{t}) = 0

t \to - \infty lim (1) = 1

= 0 + 1

Simplify

= 1

\frac{d}{d x} (0.01 (0.2 x^{2} + 4 x + 64)^{\frac{2}{3}})

\int_{0}^{10} x^{2} e^{- 0.08 x} d x

\frac{\partial}{\partial y} (y^{5} cos (3 x))

\int - \frac{x}{2} d x

\frac{( x ^{\frac{1}{3}} - 4 )}{x ^{\frac{7}{2}}}

What is the limit as t approaches-infinity of e^t+1 ?
The limit as t approaches-infinity of e^t+1 is 1