What is the integral of (x^3)/(y^2) ?

The integral of (x^3)/(y^2) is (x^4)/(4y^2)+C

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integral of (x^3)/(y^2)

\int \frac{x ^{3}}{y ^{2}} d x

\frac{x ^{4}}{4 y ^{2}} + C

Solution steps

\int \frac{x ^{3}}{y ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{y ^{2}} \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= \frac{1}{y ^{2}} \cdot \frac{x ^{4}}{4}

Simplify

\frac{1}{y ^{2}} \cdot \frac{x ^{4}}{4} : \frac{x ^{4}}{4 y ^{2}}

= \frac{x ^{4}}{4 y ^{2}}

Add a constant to the solution

= \frac{x ^{4}}{4 y ^{2}} + C

\frac{1}{( x + 1 ) ^{2}} 1

\int x^{2} 9 + x^{2} d x

\frac{1}{2002 s ^{2} + 9}

y^{^{'}} = \frac{x ^{3} y ^{3} + 4 x ^{3}}{y ^{2}}

\frac{d}{d x} (x^{2} + y^{2}) = 25

What is the integral of (x^3)/(y^2) ?
The integral of (x^3)/(y^2) is (x^4)/(4y^2)+C