What is the tangent of y=arctan(-2x),\at x=-3 ?

The tangent of y=arctan(-2x),\at x=-3 is y=-2/37 x+arctan(6)-6/37

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tangent of y=arctan(-2x),\at x=-3

tangent of

y = arctan (- 2 x), at x = - 3

y = - \frac{2}{37} x + arctan (6) - \frac{6}{37}

Solution steps

Find the tangent point:

(- 3, arctan (6))

Find the slope of

y = arctan (- 2 x) : \frac{d y}{d x} = - \frac{2}{4 x ^{2} + 1}

Compute the slope of

y = arctan (- 2 x)

x = - 3 : m = - \frac{2}{37}

Find the line with slope m=

- \frac{2}{37}

and passing through

(- 3, arctan (6)) : y = - \frac{2}{37} x + arctan (6) - \frac{6}{37}

y = - \frac{2}{37} x + arctan (6) - \frac{6}{37}

\int 14 e^{x} d x

f (x) = 1 - 6 x^{2}, (2, - 23)

\frac{\partial}{\partial x} (x y + y^{2})

x^{3} + y^{3} - 9 x y = 0, (4, 2)

\int x e^{- x^{3}} d x

What is the tangent of y=arctan(-2x),\at x=-3 ?
The tangent of y=arctan(-2x),\at x=-3 is y=-2/37 x+arctan(6)-6/37