What is the derivative of-3/(x^3) ?

The derivative of-3/(x^3) is 9/(x^4)

What is the first derivative of-3/(x^3) ?

The first derivative of-3/(x^3) is 9/(x^4)

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derivative of

- \frac{3}{x ^{3}}

\frac{9}{x ^{4}}

Solution steps

\frac{d}{d x} (- \frac{3}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 3 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 (- 3 x^{- 3 - 1})

Simplify

- 3 (- 3 x^{- 3 - 1}) : \frac{9}{x ^{4}}

= \frac{9}{x ^{4}}

\int (\frac{d y}{1})^{2} d x

\frac{\partial}{\partial x} (e^{- x - y})

\frac{\partial}{\partial y} (x^{2} y z^{2} + sin (yz))

\frac{d x}{d t} = x - x^{2}

\frac{d}{d x} (4^{3 x})

What is the derivative of-3/(x^3) ?
The derivative of-3/(x^3) is 9/(x^4)
What is the first derivative of-3/(x^3) ?
The first derivative of-3/(x^3) is 9/(x^4)