What is the derivative of 6sin(x-8e^x) ?

The derivative of 6sin(x-8e^x) is 6cos(x)-8e^x

What is the first derivative of 6sin(x-8e^x) ?

The first derivative of 6sin(x-8e^x) is 6cos(x)-8e^x

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\frac{d}{d x} (6 sin (x) - 8 e^{x})

6 cos (x) - 8 e^{x}

Solution steps

\frac{d}{d x} (6 sin (x) - 8 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 sin (x)) - \frac{d}{d x} (8 e^{x})

\frac{d}{d x} (6 sin (x)) = 6 cos (x)

\frac{d}{d x} (8 e^{x}) = 8 e^{x}

= 6 cos (x) - 8 e^{x}

\frac{d ^{2}}{d x ^{2}} (\frac{1 - 5 x}{1 + 5 x})

f (x) = 2 x^{2} - 5 x, (- 1, 7)

\frac{d}{d x} (\frac{x ^{2} + 3}{x ^{2} + 1})

\frac{d}{d x} (a^{2} + b x + c)

\frac{d}{d x} (\frac{2 x + 3}{x + 4})

What is the derivative of 6sin(x-8e^x) ?
The derivative of 6sin(x-8e^x) is 6cos(x)-8e^x
What is the first derivative of 6sin(x-8e^x) ?
The first derivative of 6sin(x-8e^x) is 6cos(x)-8e^x