What is the integral from-infinity to 0 of e^{-3x} ?

The integral from-infinity to 0 of e^{-3x} is diverges

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integral from-infinity to 0 of e^{-3x}

\int_{- \infty}^{0} e^{- 3 x} d x

diverges

Solution steps

\int_{- \infty}^{0} e^{- 3 x} d x

Compute the indefinite integral:

\int e^{- 3 x} d x = - \frac{1}{3} e^{- 3 x} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{- 3 x} d x =

diverges

= diverges

x^{3} + 2 x + 1, 2

y^{^{''}} + 64 y = 0, y (0) = 1, y^{^{'}} (0) = 5

\frac{d}{d x} (- x^{3} e^{x})

\frac{\partial}{\partial x} (x e^{(x^{2} - y)})

\int (x + 2) (3 x^{2} + 12 x) d x

What is the integral from-infinity to 0 of e^{-3x} ?
The integral from-infinity to 0 of e^{-3x} is diverges