What is (\partial)/(\partial z)(e^{xy}+z) ?

The answer to (\partial)/(\partial z)(e^{xy}+z) is 1

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(\partial)/(\partial z)(e^{xy}+z)

\frac{\partial}{\partial z} (e^{x y} + z)

1

Solution steps

\frac{\partial}{\partial z} (e^{x y} + z)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (e^{x y}) + \frac{\partial}{\partial z} (z)

\frac{\partial}{\partial z} (e^{x y}) = 0

\frac{\partial}{\partial z} (z) = 1

= 0 + 1

Simplify

= 1

\frac{d}{d x} ((x + 2)^{2} + (10 - 3 x)^{2})

n = 1 \sum \infty 1 + \frac{1}{n + 1}

x \to 0 lim (\frac{( 2 - x ) ^{3} - 8}{x})

\frac{5}{s ^{2} + 49}

y (1 + x^{2}) y^{^{'}} - x (9 + y^{2}) = 0

What is (\partial)/(\partial z)(e^{xy}+z) ?
The answer to (\partial)/(\partial z)(e^{xy}+z) is 1