What is the d/(dθ)(8cos(θ)+2sin(θ)) ?

The d/(dθ)(8cos(θ)+2sin(θ)) is -8sin(θ)+2cos(θ)

What is the first d/(dθ)(8cos(θ)+2sin(θ)) ?

The first d/(dθ)(8cos(θ)+2sin(θ)) is -8sin(θ)+2cos(θ)

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\frac{d}{d θ} (8 cos (θ) + 2 sin (θ))

- 8 sin (θ) + 2 cos (θ)

Solution steps

\frac{d}{d θ} (8 cos (θ) + 2 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (8 cos (θ)) + \frac{d}{d θ} (2 sin (θ))

\frac{d}{d θ} (8 cos (θ)) = - 8 sin (θ)

\frac{d}{d θ} (2 sin (θ)) = 2 cos (θ)

= - 8 sin (θ) + 2 cos (θ)

\frac{d y}{d x} - x e^{y} = 2 e^{y}

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + y = e^{- x} \cdot ln (x)

\frac{\partial}{\partial x} (1 + x y^{2})

h \to 0 lim (\frac{3}{h})

4 tan^{2} (7 x)

What is the d/(dθ)(8cos(θ)+2sin(θ)) ?
The d/(dθ)(8cos(θ)+2sin(θ)) is -8sin(θ)+2cos(θ)
What is the first d/(dθ)(8cos(θ)+2sin(θ)) ?
The first d/(dθ)(8cos(θ)+2sin(θ)) is -8sin(θ)+2cos(θ)