What is the limit as x approaches 4 of (-1)/(x^2-16) ?

The limit as x approaches 4 of (-1)/(x^2-16) is diverges

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limit as x approaches 4 of (-1)/(x^2-16)

x \to 4 lim (\frac{- 1}{x ^{2} - 16})

diverges

Solution steps

x \to 4 lim (\frac{- 1}{x ^{2} - 16})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (\frac{- 1}{x ^{2} - 16}) = - \infty

x \to 4 - lim (\frac{- 1}{x ^{2} - 16}) = \infty

= diverges

\frac{( x - 1 ) ^{2}}{x ^{2} + 1}

\frac{\partial}{\partial x} (\frac{( x + y )}{( x - y ) ^{2}})

h \to 0 lim (3 h + 18)

f (x) = \frac{1}{2} x ln (x^{2}), (- 1, 0)

What is the limit as x approaches 4 of (-1)/(x^2-16) ?
The limit as x approaches 4 of (-1)/(x^2-16) is diverges