What is the integral of 2/(\sqrt[3]{3x)} ?

The integral of 2/(\sqrt[3]{3x)} is 2\sqrt[3]{(x^2)/3}+1/(\sqrt[3]{3)}x^{2/3}+C

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integral of 2/(\sqrt[3]{3x)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply Integration By Parts

Simplify

Add a constant to the solution

\frac{1}{3 ^{x}}

f (x) = \frac{x ^{2} - 1}{2 x + 2}

f (x) = 4 x^{4} - 5 x^{3} + 2 x - 3

\frac{d}{d x} (\frac{x}{a ^{2} a ^{2} + x ^{2}})

\frac{d}{d x} (25 ln (x^{2}) - x^{2})

What is the integral of 2/(\sqrt[3]{3x)} ?
The integral of 2/(\sqrt[3]{3x)} is 2\sqrt[3]{(x^2)/3}+1/(\sqrt[3]{3)}x^{2/3}+C