What is the limit as t approaches 1 of sqrt(t+3) ?

The limit as t approaches 1 of sqrt(t+3) is 2

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limit as t approaches 1 of sqrt(t+3)

t \to 1 lim (t + 3)

2

Solution steps

t \to 1 lim (t + 3)

Plug in the value

t = 1

= 1 + 3

Simplify

1 + 3 : 2

= 2

f (x) = 2 x^{2} - 5 x + 3

x \to 0 + lim (ln (1 + x))

y = 5 tan (x), (\frac{π}{4}, 5)

f (x) = \frac{2}{x}, (- 4, - \frac{1}{2})

\frac{d}{d x} (x^{2} (x + 3)^{4})

What is the limit as t approaches 1 of sqrt(t+3) ?
The limit as t approaches 1 of sqrt(t+3) is 2