What is the sum from n=1 to infinity of (5^n)/(6^nn) ?

The sum from n=1 to infinity of (5^n)/(6^nn) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (5^n)/(6^nn)

n = 1 \sum \infty \frac{5 ^{n}}{6 ^{n} n}

converges

Solution steps

n = 1 \sum \infty \frac{5 ^{n}}{6 ^{n} n}

Apply Series Ratio Test:

converges

= converges

x y^{^{'}} + y = 3 x y

\int (x^{2} + 7 x - 3) sin (2 x) d x

\int \frac{3}{x ( x ^{2} + 1 )} d x

\frac{d}{d x} (∣ (- 3)^{x} ∣)

y^{^{'}} x^{2} + y x^{2} = x y^{5}

What is the sum from n=1 to infinity of (5^n)/(6^nn) ?
The sum from n=1 to infinity of (5^n)/(6^nn) is converges