What is the integral of sin(u)cos(u) ?

The integral of sin(u)cos(u) is (sin^2(u))/2+C

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integral of sin(u)cos(u)

\int sin (u) cos (u) d u

\frac{sin ^{2} ( u )}{2} + C

Solution steps

\int sin (u) cos (u) d u

Apply u-substitution

: \int v d v

= \int v d v

Apply the Power Rule

: \frac{v ^{2}}{2}

= \frac{v ^{2}}{2}

Substitute back

v = sin (u)

= \frac{sin ^{2} ( u )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( u )}{2} + C

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What is the integral of sin(u)cos(u) ?
The integral of sin(u)cos(u) is (sin^2(u))/2+C