What is the integral from 1 to 8 of x^{-8/3} ?

The integral from 1 to 8 of x^{-8/3} is 93/160

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integral from 1 to 8 of x^{-8/3}

\int_{1}^{8} x^{- \frac{8}{3}} d x

\frac{93}{160}

Decimal Notation

0.58125

Solution steps

\int_{1}^{8} x^{- \frac{8}{3}} d x

Apply the Power Rule

: [- \frac{3}{5 x ^{\frac{5}{3}}}]_{1}^{8}

= [- \frac{3}{5 x ^{\frac{5}{3}}}]_{1}^{8}

Compute the boundaries:

\frac{93}{160}

= \frac{93}{160}

y = x^{2} + 9, y = 10 + 2 x

x \to 3 lim (x^{2} - 9)

\int 3 cos (t) - 2 sin (t) d t

e^{4 t} (t^{2} + 3 t + 5)

\int (- 9 x^{2} sec (3 x^{3} + 1)) d x

What is the integral from 1 to 8 of x^{-8/3} ?
The integral from 1 to 8 of x^{-8/3} is 93/160