What is the sum from n=1 to infinity of ((-1)/2)^n ?

The sum from n=1 to infinity of ((-1)/2)^n is converges

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sum from n=1 to infinity of ((-1)/2)^n

n = 1 \sum \infty (\frac{- 1}{2})^{n}

converges

Solution steps

n = 1 \sum \infty (\frac{- 1}{2})^{n}

Simplify

= n = 1 \sum \infty (- \frac{1}{2})^{n}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial x} ((4 x + 4 y) e^{y})

2 e^{- t} cos (2 t)

\frac{d}{d x} (\frac{3 x ^{2} - 2}{x})

n = 0 \sum \infty \frac{( 1 0 ^{2 n} )}{n !}

n = 1 \sum \infty (\frac{n}{n + 7})^{n}

What is the sum from n=1 to infinity of ((-1)/2)^n ?
The sum from n=1 to infinity of ((-1)/2)^n is converges