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Popular >

(x^2+9)y^'+xy=0

Solution

(x^{2} + 9) y^{^{'}} + x y = 0

Solution

y = \frac{c _{1}}{x ^{2} + 9}

Solution steps

(x^{2} + 9) y^{'} (x) + x y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} + 9}

y = \frac{c _{1}}{x ^{2} + 9}

Popular Examples

d/(dy)(xcos(y))

\frac{d}{d y} (x cos (y))

integral of (x^3+x^2)/(x^2+5x+6)

\int \frac{x ^{3} + x ^{2}}{x ^{2} + 5 x + 6} d x

derivative of (x^2e^x/(x^2+e^x))

\frac{d}{d x} (\frac{x ^{2} e ^{x}}{x ^{2} + e ^{x}})

y^{''}-4y^'+4y^'=0

y^{^{''}} - 4 y^{^{'}} + 4 y^{^{'}} = 0

integral of cos^3(x/(12))

\int cos^{3} (\frac{x}{12}) d x

Frequently Asked Questions (FAQ)

What is the solution for (x^2+9)y^'+xy=0 ?
The solution for (x^2+9)y^'+xy=0 is y=(c_{1})/(sqrt(x^2+9))