What is the derivative of 5e^x+x ?

The derivative of 5e^x+x is 5e^x+1

What is the first derivative of 5e^x+x ?

The first derivative of 5e^x+x is 5e^x+1

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derivative of

5 e^{x} + x

5 e^{x} + 1

Solution steps

\frac{d}{d x} (5 e^{x} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 e^{x}) + \frac{d x}{d x}

\frac{d}{d x} (5 e^{x}) = 5 e^{x}

\frac{d x}{d x} = 1

= 5 e^{x} + 1

\int k \cdot x d x

(x, y) \to (0, 4) lim (x^{3} y)

f (x) = ln (2), y = 0, y = 2

\int_{0}^{1} (x^{2} + 6) e^{- x} d x

y = \frac{1}{x - 5}

What is the derivative of 5e^x+x ?
The derivative of 5e^x+x is 5e^x+1
What is the first derivative of 5e^x+x ?
The first derivative of 5e^x+x is 5e^x+1