What is (\partial)/(\partial y)(2yt+xj) ?

The answer to (\partial)/(\partial y)(2yt+xj) is 2t

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(\partial)/(\partial y)(2yt+xj)

\frac{\partial}{\partial y} (2 y t + x j)

2 t

Solution steps

\frac{\partial}{\partial y} (2 y t + x j)

Treat

j, t, x

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 y t) + \frac{\partial}{\partial y} (x j)

\frac{\partial}{\partial y} (2 y t) = 2 t

\frac{\partial}{\partial y} (x j) = 0

= 2 t + 0

Simplify

= 2 t

\int \frac{x ^{2}}{16 + x ^{2}} d x

\int 4 t^{3} y - 15 t^{2} - y d t

11 x - 3, 10 x - 5, [12, 34]

\int \frac{1}{t ^{2} + 1} d t

x \to 129 lim (\frac{x - 129}{x + 15 - 12})

What is (\partial)/(\partial y)(2yt+xj) ?
The answer to (\partial)/(\partial y)(2yt+xj) is 2t