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Popular >

4y+y^{''}=0

Solution

4 y + y^{^{''}} = 0

Solution

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

4 y + y^{''} (t) = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Popular Examples

derivative of (1/(x^2)-3/(x^4))(x+9x^3)derivative of

(\frac{1}{x ^{2}} - \frac{3}{x ^{4}}) (x + 9 x^{3})

integral of 2/((1+x^2)^2)

\int \frac{2}{( 1 + x ^{2} ) ^{2}} d x

(d^2y)/(dt^2)+10(dy)/(dt)+25y=0

\frac{d ^{2} y}{d t ^{2}} + 10 \frac{d y}{d t} + 25 y = 0

derivative of (x^3y+xy^3/(x^2+y^2))

\frac{d}{d x} (\frac{x ^{3} y + x y ^{3}}{x ^{2} + y ^{2}})

tangent of f(x)=sqrt(x-4),(13,3)tangent of

f (x) = x - 4, (13, 3)

Frequently Asked Questions (FAQ)

What is the solution for 4y+y^{''}=0 ?
The solution for 4y+y^{''}=0 is y=c_{1}cos(2t)+c_{2}sin(2t)