What is the derivative of f(x)=2x^2+7x ?

The derivative of f(x)=2x^2+7x is 4x+7

What is the first derivative of f(x)=2x^2+7x ?

The first derivative of f(x)=2x^2+7x is 4x+7

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derivative of

f (x) = 2 x^{2} + 7 x

4 x + 7

Solution steps

\frac{d}{d x} (2 x^{2} + 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (7 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (7 x) = 7

= 4 x + 7

x^{4} + 7 e^{x}

y = e^{3 x}, at x = \frac{1}{3} ln (5)

\frac{\partial}{\partial x} (\frac{5 x}{2 y})

\int_{0}^{1} (e^{- 0.2 t}) d t

\int_{0}^{1} 1 + (2 - x^{2})^{2} d x

What is the derivative of f(x)=2x^2+7x ?
The derivative of f(x)=2x^2+7x is 4x+7
What is the first derivative of f(x)=2x^2+7x ?
The first derivative of f(x)=2x^2+7x is 4x+7