What is the derivative of f(2)=(x^2-4)/(x-2) ?

The derivative of f(2)=(x^2-4)/(x-2) is 1

What is the first derivative of f(2)=(x^2-4)/(x-2) ?

The first derivative of f(2)=(x^2-4)/(x-2) is 1

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derivative of

f (2) = \frac{x ^{2} - 4}{x - 2}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 4}{x - 2})

Simplify

\frac{x ^{2} - 4}{x - 2} : x + 2

= \frac{d}{d x} (x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 1 + 0

Simplify

= 1

\frac{\partial}{\partial t} (\frac{( 3 r + s )}{t})

\frac{d ^{2} x}{d t ^{2}} = - k x

\frac{d}{d x} ((8 x^{2} - 2 x) (5 x + 9))

y^{^{''}} - 4 y^{^{'}} + 53 y = 0

\frac{d}{d x} ((x^{5} + 1)^{6})

What is the derivative of f(2)=(x^2-4)/(x-2) ?
The derivative of f(2)=(x^2-4)/(x-2) is 1
What is the first derivative of f(2)=(x^2-4)/(x-2) ?
The first derivative of f(2)=(x^2-4)/(x-2) is 1