What is (\partial)/(\partial x)(9-3x^2-y^2) ?

The answer to (\partial)/(\partial x)(9-3x^2-y^2) is -6x

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(\partial)/(\partial x)(9-3x^2-y^2)

\frac{\partial}{\partial x} (9 - 3 x^{2} - y^{2})

- 6 x

Solution steps

\frac{\partial}{\partial x} (9 - 3 x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9) - \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (9) = 0

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 - 6 x - 0

Simplify

= - 6 x

x \to 2 lim (3 - x^{2})

n = 0 \sum \infty 3

y^{^{'}} = y sin (2 x)

\int (5 x - 1) (3 x^{3} + 2) d x

\frac{\partial}{\partial y} (x (x + y))

What is (\partial)/(\partial x)(9-3x^2-y^2) ?
The answer to (\partial)/(\partial x)(9-3x^2-y^2) is -6x